The calculation of filamentary photon force and its
momentum transition period

The method of calculating and the amount of corpuscular photon force
have been presented in conformity with the below document, by the
American Physics Society:

Now, our suggested method for the calculation of filamentary photon
force and finding its relation with the electromagnetic wave
frequency, as follows:

As we know, Energy is equal to the Force multiplied by the Distance,
it means:

E denotes Energy, F is Force and Distance is referred to by d. As we
know, total energy of photon or electromagnetic wave quantum is
achieved through the Planck's known relation formula, means:

Ep
is the photon energy, h is Planck's Constants, and f is the
electromagnetic wave frequency. Look at the following figure:

The layout of equations to calculate filamentary photon force could
be seen in the first step as:

Eλ
is the energy for each cycle equal to h (Planck's Constants), λ is
the wavelength, Fp
is the filamentary photon force and Pp is the photon's
momentum. As it was told in the chapter Particle or stringy
photon, one or few-seconds photon, energy packaging in space-time,
photon is a quantum filament with the number of f times λ wavelength
which can transmit or induce its momentum or total energy to
obstacle or balance level entirely and in a lump. So, the equations
will be propounded exactly as follows:

And this is just the same as - but in a new method - previously
achieved result, presented by the American Physics Society, which
proves more clear and simple that photon or electromagnetic energy
quantum is a filament of the wavelengths equal to the wave
frequency, like the same matters told in the chapter Particle or stringy
photon, one or few-seconds photon, energy packaging in space-time,
and the important point that photon is not carrying the forces in
electromagnetic field, but is the holder of the force and
oscillation energy in an alternative variant electromagnetic field.
Since, a static field with no oscillation will have no radiation
like waves or photons, and concerning the equations for mass,
energy, momentum and photon force while the electromagnetic wave
frequency is zero, all the physical components of photon will be
zero and simply, there will be no quantum. We can reach the
following general conclusion for the filamentary photon force:

c is the velocity of
light and mp
is the photon's mass. The reason for the excessive photon force is
that filamentary photon is able to transmit or induce its momentum
or energy to the obstacle or balance level, in a very short time.
This time duration, is equal to the required time for oscillating an
electromagnetic wave cycle. Means:

Δt is the time to transmit filamentary photon momentum. Since, the
relation between force and momentum is:

ΔP is the amount of transmitted momentum. The relation between the
force and filamentary photon momentum will be:

ΔPp
is the amount of transmitted photon's momentum and if all the
momentum for the filamentary photon transmitted, we'll surely reach
the same results as previous:

In fact, the force of filamentary photon has direct relations with
square root of electromagnetic wave frequency.

The diagram of frequency and filamentary photon energy

The diagram of frequency and filamentary photon momentum

The diagram of frequency and filamentary photon force