As we knew, to change temperature of m
kilogram of a material with specific heat C in amount of
ΔӨ,
it needs Q Joule of thermal energy. From definition of specific
heat, we have:
In other words:
Which Q (energy) is at Joule, m (mass)
at kilogram, C (specific heat) at Joule per kilogram Celsius degree,
and
ΔӨ
(temperature change) at Celsius. Now to calculate thermal potential
energy of a material, we use below equation:
Which in above equation UQ
(thermal potential energy) at Joule, m (mass) at kilogram, C
(specific heat) at Joule per kilogram Celsius degree and
Ө
(temperature) at Kelvin degree. For example, one kilogram of steel
with 500 Joule per kilogram Celsius degree as specific heat and 37
Celsius degree as temperature (273+37=310 Kelvin degree) :
It has 155 kilo Joules as saved thermal
energy which if catch it, its temperature will be absolute zero. As
we know, by increasing velocity, the mass of material will be
increased too and this amount of mass increase will be calculated
from below equation:
m is mass of on move material, m0
is mass of static material, v is velocity of material movement, and
c is light velocity. Now by replacing on move mass in previous
equation, the new below equation will be attained in order to check
the temperature measure of the on move material:
Ө
In this equation is the temperature of the on move material that
this equation expresses this matter that if the on move material has
no temperature exchange with the surrounded environment (its thermal
potential energy is consonant), its temperature will be closed to
absolute zero with increasing material velocity to light velocity.
Because:
Now we shall draft the equation that
shows the relation between temperature of static material and
temperature of same material but on move with certain velocity. For
this, we put the physical equivalent of UQ for
the static material in above equation:
Ө0
is the temperature of the static
material that finally we reach to a simple equation that is similar
to Gerald – Lorentz equation for shortening length and slowing time
toward velocity increase. Now we draw the diagram of a material
with 37 Celsius degree or 310 Kelvin degree as temperature, when it
is closing to light velocity:
So it seems as closing to light
velocity, the material temperature will tend to absolute zero, this
will lead to a thermal balance which surely prevent occurring
explosion because of mass and density increase.
